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How many terms are there in the AP 41, 38, 35, ….,8? |
Answer» In the given AP, a = 41 and d = (38 - 41) = -3 Suppose that there are n terms in the given AP. Then Tn = 8 \(\Rightarrow\) a + (n - 1) d = 8 \(\Rightarrow\) 41 + (n - 1) x (-3) = 8 \(\Rightarrow\) 3n = 36 \(\Rightarrow\) n = 12 Hence, there are 12 terms in the given AP. |
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