InterviewSolution
Saved Bookmarks
| 1. |
How many terms of the G.P. 3, 3/2, 3/4, … Be taken together to make 3069/512 ? |
|
Answer» Given: Sum of G.P = 3069/512 Where, a = 3, r = (3/2)/3 = 1/2, n = ? By using the formula, Sum of GP for n terms = a(rn – 1 )/(r – 1) 3069/512 = 3 ((1/2)n – 1)/ (1/2 – 1) 3069/512 × 3 × 2 = 1 – (1/2)n 3069/3072 – 1 = – (1/2)n (3069 – 3072)/3072 = – (1/2)n -3/3072 = – (1/2)n 1/1024 = (1/2)n (1/2)10 = (1/2)n 10 = n ∴ 10 terms are required to make 3069/512 |
|