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InterviewSolution
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How many times does the mean free path of nitrogen molecules exceed the mean distance between the molecules under standard conditions ? |
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Answer» The mean distance between molecules is of the order `((22.4 xx 10^-3)/(6.0 xx 10^23))^(1//3) = ((224)/(6))^(1//3) xx 10^-9 metres ~~ 3.34 xx 10^-9 metres` This is about `18.5` times smaller than the mean free path calculated in `2.223(a)` above. |
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