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How many times more intense is a `90 dB` sound than a `40 dB` sound?A. `2.5`B. `5`C. `50`D. `10^(5)`

Answer» Correct Answer - D
`L_(2) - L_(1) = 10log_(10) ((I_(2))/(I_(1)))`
`(90 - 40) = 10 log_(10) ((I_(2))/(I_(1)))`
`(I_(2))/(I_(1)) = 10^(5)`


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