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How many words can be formed by using the letters of the word ORIENTAL so that A and E always occupy the odd places? |
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Answer» There are 4 odd places in the word ∴ Number of permutations = 4P2 = 4!/2! = 12 Now the remaining 6 places filled with remaining 6 letters ∴ Number of permutations = 6P6 = 6!/0! = 720 Hence the total number of permutations = 12 × 720 = 8640 |
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