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How much time a satellite in an orbitat height 35780 km above earth's sur-face would take, if the mass of theearth would have been four times itsoriginal mass?. |
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Answer» Use the formula, Here, T is time period, R is orbit radius G is gravitational constant and is mass of earth. Given, = 4 × original mass of earth, = 4 × 5.92 × 10²⁴ kg Orbit radius , R = Earth's radius + height of satellite from Earth's surface = 6400 km + 35780 km = 42180 km = 4.2180 × 10⁷ m G = 6.67 × 10⁻¹¹ Nm²/Kg² Now, T = 2π√{(4.2180 × 10⁷)³/(6.67 × 10⁻¹¹) × (4 × 5.92 × 10²⁴)} = 43309.8 sec So, T = 43309.8/3600 ≈ 12 hrs Hence, time to complete revolution by satellite is 12 hrs |
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