How much time does it take in induced radioactivity to reduce radio ph

1.	How much time does it take in induced radioactivity to reduce radio phosphorus to 1/32 of its initial valuea)15 minb)150 secc)15 hrd)1.5 min(please give me a explanation for this answer)
Answer» Answer: we KNOW, HALF life of P-32 is 14.29 days $\frac{1}{2} part \: will \: disintegrate \: in \: 14.29 \: dys \\ (\frac{1}{2} of \: \frac{1}{2} ) = \frac{1}{4} \: will \: diintegrate \: in \: 14.29 \: days \\ (\frac{1}{2} of \: \frac{1}{4}) = \frac{1}{8} will \: disintegrate \: in \: 14.29 \: dys \\ (\frac{1}{2} of\frac{1}{8} ) = \frac{1}{16} will \: disintegrate \: in \: 14.29 \: days \\ \frac{1}{2} of \: \frac{1}{16} = \frac{1}{32} will \: disintegrate \: in \: 14.29 \: days$ so, TOTAL time taken=(14.29×5) days=71.45 days

How much time does it take in induced radioactivity to reduce radio phosphorus to 1/32 of its initial valuea)15 minb)150 secc)15 hrd)1.5 min(please give me a explanation for this answer)

Answer»

Answer:

we KNOW, HALF life of P-32 is 14.29 days

$\frac{1}{2} part \: will \: disintegrate \: in \: 14.29 \: dys \\ (\frac{1}{2} of \: \frac{1}{2} ) = \frac{1}{4} \: will \: diintegrate \: in \: 14.29 \: days \\ (\frac{1}{2} of \: \frac{1}{4}) = \frac{1}{8} will \: disintegrate \: in \: 14.29 \: dys \\ (\frac{1}{2} of\frac{1}{8} ) = \frac{1}{16} will \: disintegrate \: in \: 14.29 \: days \\ \frac{1}{2} of \: \frac{1}{16} = \frac{1}{32} will \: disintegrate \: in \: 14.29 \: days$

so, TOTAL time taken=(14.29×5) days=71.45 days

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