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How much time is requred for two - third completion of a first order reaction having, `K=5.48xx10^(-14)S^(-1)`?A. `2.01xx10^(11)s`B. `2.01xx10^(13)s`C. `8.08xx10^(13)s`D. `16.04xx10^(11)s` |
Answer» Correct Answer - B Time required for two-third completion of a first order reaction, `[A]_(0)=a,[A]=a-(2)/(3)a=(a)/(3)` `t_(t//2)=(2.303)/(k)"log"([A]_(0))/([A])=(2.303)/(K)"log"(a)/(a/3)` `=(2.303)/(K) "log"3` `t(1//2)=(2.303xx0.4771)/(5.48xx10^(-14))=2.01xx10^(13)s` |
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