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How much will the reduction potential of a hydrogen electrode change when its solution initially at `pH=0` is neutralized to `pH=7` ?A. increase by `0.059V`B. decrease by `0.059V`C. increase by 0.41 VD. decrease by 0.41 V |
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Answer» Correct Answer - D `H^(+)+e^(-)to(1)/(2)H_(2),E=0-(0.0591)/(1)log_(10)((1)/([H^(+)]))=+0.591log_(10)[H^(+)]` `E_(1)=0{pH=0}` `E_(2)=+0.0591log_(10)[10^(-7)]=-0.0591xx7{atpH=7}=-0.41V` |
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