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How to solv this matrix​

Answer»

\boxed{ \underline{ \underline{{ \huge{ \textbf{ \textsf{A}}}} \textbf{NSWER - }}}}

FIND the VALUE of X , y , z , t where -

{ \mathtt{\left[ \begin{array}{c c } \sf x + 3& \sf x + 2y \\\\ \sf \: z - 1& \sf \: 4t - 6 \end{array} \right] = \left[ \begin{array}{c c } \sf 0& \sf - 7 \\\\ \sf \: 3& \sf \: 2t \end{array} \right] }} \\ \\ \\ \implies{ \mathtt{x + 3 = 0}} \\ \boxed{ \implies{ \mathtt{x = - 3}}} \\ \\ \implies{ \mathtt{x + 2y = - 7}} \\ \implies{ \mathtt{ - 3 + 2y = - 7}} \\ \implies{ \mathtt{2y = - 7 + 3}} \\ \implies{ \mathtt{2y = - 4}} \\ \implies{ \mathtt{y = \frac{ \cancel{ - 4} ^{2} }{ \cancel2} }} \\ \boxed{ \implies{ \mathtt{y = - 2}}} \\ \\ \implies{ \mathtt{z - 1 = 3}} \\ \implies{ \mathtt{z = 3 + 1}} \\ \boxed{\implies{ \mathtt{z = 4}}} \\ \\ \implies{ \mathtt{4t - 6 = 2t}} \\ \implies{ \mathtt{4t - 2t = 6}} \\ \implies{ \mathtt{2t = 6}} \\ \implies{\mathtt{t = \frac{ \cancel6 ^{3} }{ \cancel2} }} \\ \boxed{ \implies{ \mathtt{t = 3}}}

{ \mathtt{ \therefore{ \purple{ \: x = - 3 \: \: \: \: \: \: \: y = - 2 }}}} \\{ \mathtt{ \purple{z = 4 \: \: \: \: \: \: \: \: \: \: \: \: t = 3}}}

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