How will the rate of reaction `2SO_(2)(g) + O_(2)(g) rarr 2SO_(3)(g)` change if the volume of the reaction vessel is halved?A. (a) It will br `1//16th` of its initial value.B. (b) it will be `1//4th` of its initial value.C. It will be `8` times of its initial value.D. It will be `4` times of its initial value.

How will the rate of reaction `2SO_(2)(g) + O_(2)(g) rarr 2SO_(3)(g)`

1.	How will the rate of reaction `2SO_(2)(g) + O_(2)(g) rarr 2SO_(3)(g)` change if the volume of the reaction vessel is halved?A. (a) It will br `1//16th` of its initial value.B. (b) it will be `1//4th` of its initial value.C. It will be `8` times of its initial value.D. It will be `4` times of its initial value.
Answer» Correct Answer - C `V = (1)/(2)`, then concentration `= 2` times, Assuming the rate law as: `r_(1) = k[SO_(2)]^(2)[O_(2)]` `r_(2) = k[2SO_(2)]^(2)[2O_(2)]` `r_(2) = 8r_(1)`Correct Answer - C `V = (1)/(2)`, then concentration `= 2` times, Assuming the rate law as: `r_(1) = k[SO_(2)]^(2)[O_(2)]` `r_(2) = k[2SO_(2)]^(2)[2O_(2)]` `r_(2) = 8r_(1)`

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