Hydrogen when subjected to photon disocation, yieds one normal atom and atom possessing `1.97 eV` more energy than normal atom .The bond dissociation energy of hydrogen molecule into normal atom is `103 `kcal `mol^(-1)` . Campate the wavelength of effective photon for photo dissociation of hydrogen molecule in the given case

Hydrogen when subjected to photon disocation, yieds one normal atom an

1.	Hydrogen when subjected to photon disocation, yieds one normal atom and atom possessing `1.97 eV` more energy than normal atom .The bond dissociation energy of hydrogen molecule into normal atom is `103 `kcal `mol^(-1)` . Campate the wavelength of effective photon for photo dissociation of hydrogen molecule in the given case
Answer» `H_(2) rarr H + H^(o+)` where H is atom and `H^(o+)` is excited H atom so the energy required to dissociate `H_(2)` in this marmer will be greater then the bond energy of `H_(2)` + extra energy of `E_(("absorbed"))` = dissociate energy of `H_(2)` + extra exrtra energy of excuted atom Energy required to dissociation in normal mather `= 103 xx 10^(3) cal` `= (103 xx 10^(3) xx (4.18))/(6 xx 10^(23))` `= 7.716 xx 10^(-19) J atom ^(-1)` The extra energy possessed by the excited atomk in `1.97 eV= 1.97 xx 1.6 xx 10^(-19) + 3.152 xx 10^(-19)` `E_(("abesorbed")) = 7.17 xx 10^(-19) + 3.152 xx 10^(-19) = 1.080668 xx 10^(-19) J` Now calculate the wavelength of photon corresponding this energy `lambda= (hc)/(E ) = (6.63 xx 10^(-34) xx 3xx 1100^(8))/(1.0868 xx 10^(-18))` `= 1.830 xx 10^(-7)m = 1830 Å`

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