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I. At what angle two forces (P +Q) and (P-Q) shouldbe inclined so as to have a resultant V (3P2+Q2)?

Answer»

forces are (P+Q) and (P-Q)Resultant R is (3P^2 +Q^2)^0.5resultant for A,B : R^2 = A^2 +B^2 +2ABcosxR^2=(P+Q)^2 +(P-Q)^2 +2 (P+Q)(P-Q)cosx3P^2 +Q^2 =P^2 +Q^2 +2PQ+P^2 +Q^2-2PQ+2(P-Q)(P+Q)cosx3P^2 +Q^2=2P^2 +2Q^2+2(P-Q)(P+Q)cosxP^2 -Q^2 =(P^2 -Q^2)cosxcosx=1x=0vectors are parallel



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