InterviewSolution
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InterviewSolution
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(i) Explain Soddy and Fajan Radioactive displacement law. (ii) Calculate the ph of 0.05MH_2SO_4. |
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Answer» Solution :Alpha decay : (a) Unstable parent nucleus emits an alpha particle to form stable daughter nucleus. (b) `""_(92)U^(238)RARR ""_(90)Th^(234)+""_2He^4(alpha-"decay")` (C) Mass number decreases by 4. (d) Atomic number decreases by 2. Beta decay : (a) Unstable parent nucleus emits a beta particle to form stable daughter nucleus . (b) `""_15P^(32)rarr_(16)S^(32)+_(-1)e^(theta)(beta-"decay")` (c) Mass number - no change (d) Atomic number increased by 1. Gamma decay: (a) The atomic number and the mass number remain same . (b) Te energy level of the nuceleus change. `[H^+]` = Normality = MOLARITY `xx` basicity `=0.05xx2 = 0.1` `=10^(-1)= 1 xx10^(-1)` `pH = -log _(10) [H^+]` `pH = -log _(10) 1 xx 10^(-1)` `pH = - log _(10)1 - log _(10) 10^(-1)` `pH = 0-(-1log_(10)10)=1` |
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