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I) Find the dimensions of (i) Power, (ii) Force and(iii) Permittivity of vacuum (Ea). |
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Answer» i)Power= Work/TimeDimensional Formula of Work= M1L2T-2Divide it by Time T1So Dimensional Formula of Power= M1L2T-3ii)Force = Mass x AccelerationAcceleration = Change in Velocity/Time TakenAcceleration = M0L1T-2Substituting this in Force formula we getForce = Mass x AccelerationForce = M x M0L1T-2 So Dimensional Formula of Force= M1L1T-2 iii)PEMITTIVITY= (CHARGE)^2 /(FORCE)*(DISTANCE)^2 =[TA]^2 / [MLT^ -2] [L]^2 =[TA]^2 / [ML^3T^ -2] =[M^ -1 L^ -3 T^2+2 A^2] = [M^ -1 l^ -3 T^4 A^2] |
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