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I. For a body in S.H.M. the velocity is givenms. The4)48msby the relation V-144-16xmaximum acceleration is1) 12 m/s' 2) 16ms 3)36m/s

Answer»

The expression of velocity in S.H.M is

V² = ω²(a² -x²) here.. a = maximum amplitude and ω is the frequency..

so, compraing V = √144-16x² = √(12)²-(4x)² , we get ω (as coefficients of x)= 4 and a as √9 = 3m

so, maximum acceleration is aω² = 3*4*4 = 48m/s²

so option D



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