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`I` is moment of inertia of a thin circular ring about an axis perpendicular to the plane of ring and passing through its centre. The same ring is folded into `2` turns coil. The moment of inertia of circular coil about an axis perpendicular to the plane of coil and passing through its centre isA. `2I`B. `4I`C. `I/2`D. `I/4` |
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Answer» Correct Answer - D Mass is same, `l=2pirnrArrr alpha1/n` where `n` is number of turns `Ipropr^(2)` and `(I_(1))/(I_(2))=((r_(1))/(r_(2)))^(2)=((n_(2))/(n_(1)))^(2)` |
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