Saved Bookmarks
| 1. |
(i) Write the electron-dot structures for sodium (11) oxygen (8), chlorine (17) and magnesium (12) show the formation of Na_(2)O and MgO by the transfer of electrons. (ii) Name the ions present in these compounds. |
|
Answer» Solution :(i) SODIUM (NA) - 2,8,1 `overset(**)(Na)` Chlorine (Cl) - 2,8,7 `.^(*)overset(..)underset(..)Cl:` Oxygen (O) - 2,6 `:overset(..)O:` Magnesium (Mg) - 2,8,2 Mg: `{:(Mg,RARR,Mg^(2+)+2e^(-),),("2,8,2",,"2,8",),(,,"(Magnesium cation)",),(O+2e^(-),rarr,O^(2-),),("2,6",,"2,8",):}`  `{:(Na,rarr,Na^(+)+e^(-),),("2,8,1",,"2,8",),(O+2e^(-),rarr,O^(2-),),("2,6",,"2,8",):}`  (ii) In MGO, cation - `Mg^(2+)`, Anion - `O^(2)` In `Na_(2)O`, cation - `Na^(+)`, Anion - `O^(2)` |
|