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Ice at `0^@C` is added to 200 g of water initially at `70^@C` in a vacuum flask. When 50 g of ice has been added and has all melted the temperature of the flask and contents is `40^@C`. When a further 80 g of ice has been added and has all melted the temperature of the whole becomes `10^@C`. Find the latent heat of fusion of ice. |
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Answer» Correct Answer - A::C Let heat capacity of flask is C and latent heat of fusion of ice is L. Then, `C(70-40)+200 xx 1 xx (70-40) = 50L` `+50 xx 1xx (40 -0)` or `3C - 5L = -400 ……(i)` Further, `C(40-10)+250 xx 1 xx (40-10)` `=80L + 80 xx 1 xx (10 -0)` or `3C - 8L = -670` .......(ii) Solving Eq. (i) and (ii), we have `L = 90 cal//g` |
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