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Identify the correct condition for a semiconductor to be electrically neutral.(a) Nd+p=Na+n(b) Nd-p=Na+n(c) Nd+p=Na-n(d) Nd-p=Na-nI have been asked this question in an interview for job.My question is from Charge Densities in a Semiconductor impurities topic in chapter Conduction in Semiconductors of Electronic Devices & Circuits

Answer»

Correct OPTION is (a) Nd+p=Na+n

The EXPLANATION: The SUM of the NUMBER of DONORS and the holes is equal to the sum of the number of the acceptors and the electrons.



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