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If `0lexle1` then `tan{1/2sin^(-1)((2x)/(1+x^(2)))+1/2cos^(-1)((1-x^(2))/(1+x^(2)))}` is equal toA. `(2x)/(1-x^(2))`B. 0C. `(2x)/(1+x^(2))`D. x |
Answer» We know that `sin^(-1)(2x)/(1+x^(2))=2tan^(-1)xif -1 lexle1` and `cos^(-1)(1+x^(2))/(1+x^(2))=2tan^(-1)x if 0lexleinfty` `therefore tan{1/2sin^(-1)(2x)/(1+x^(2))+1/2cos^(-1)(1-x^(2))/(1+x^(2))}` `=tan(tan^(-1)(2x)/(1-x^(2)))=(2x)/(1-x^(2))` |
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