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If `2^2pi//sin^((-1)x)-2(a+2)^pi//sin^((-1)x)+8a |
Answer» Correct Answer - D `2^(2pi//sin^(-1)x) - 2 (a + 2) 2^(pi//sin^(-1) x) + 8a lt 0` `(2^(pi//sin^(-1)x) - 4) (2^(pi//sin^(-1)x) - 2a) lt 0` Now `2^(pi//sin^(-1) x) in (0, (1)/(4)] uu [4, oo)` For `2^(pi//sin^(-1)x) in (0, (1)/(4)]`. We have `(2^(pi//sin^(-1)x) -4) lt 0` `:. 2^(pi//sin^(-1)x) -2a gt 0` or `2a lt (1)/(4)` or `0 le a (1)/(8)` Similarly, for `2^(pi//sin^(-1) x) in [4, oo), a gt 2`, we get So, `a in [0, (1)/(8)) uu (2, oo)` |
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