1.

If (2p +1), 13, (5p - 3) are in AP, find the value of p.

Answer»

Let (2p + 1), 13, (5p - 3) be three consecutive terms of an AP.

Then 13 - (2p + 1) = (5p - 3) - 13

\(\Rightarrow\) 7p = 28

\(\Rightarrow\) p = 4

∴ When p = 4,(2p + 1),13 and (5p - 3) from three consecutive terms of an AP.



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