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If `3A rarr 2B`, then the rate of reaction of `+ (dB)/(d t)` is equal toA. `- (3)/(2) (d[A])/(dt)`B. `- (2)/(3) (d[A])/(dt)`C. `- (1)/(3) (d[A])/(dt)`D. `+ 2(d[A])/(dt)` |
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Answer» Correct Answer - B For the reaction `3Ararr2B` `Rate `=-(d[A])/(3dt)=+(d[B])/(2dt)` Thus, `+(d[B])/(dt)=-(2)/(3)=-(2)/(3)(d[A])/(dt)` |
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