If `3A rarr 2B`, then the rate of reaction of `+ (dB)/(d t)` is equal toA. `-(3)/(2)(d[A])/(dt)`B. `-(2)/(3)(d[A])/(dt)`C. `-(1)/(3) (d[A])/(dt)`D. `+2(d[A])/(dt)`

If `3A rarr 2B`, then the rate of reaction of `+ (dB)/(d t)` is equal

1.	If `3A rarr 2B`, then the rate of reaction of `+ (dB)/(d t)` is equal toA. `-(3)/(2)(d[A])/(dt)`B. `-(2)/(3)(d[A])/(dt)`C. `-(1)/(3) (d[A])/(dt)`D. `+2(d[A])/(dt)`
Answer» Correct Answer - B For reaction `3A to 2B` `rate =-(1)/(3) (d[A])/(dt)`[ Rate of disappearance ] `=+(1)/(2)(d[B])/(dt)`[ rate of appearance ] `therefore + (d[B])/(dt) =-(2)/(3) (d[A])/(dt)`

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If `3A rarr 2B`, then the rate of reaction of `+ (dB)/(d t)` is equal toA. `-(3)/(2)(d[A])/(dt)`B. `-(2)/(3)(d[A])/(dt)`C. `-(1)/(3) (d[A])/(dt)`D. `+2(d[A])/(dt)`

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