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If 4 bulbs are there each of which can be defective or non-defective then what is the total number of possible outcomes?(a) 8(b) 16(c) 4(d) 2This question was posed to me by my college director while I was bunking the class.This is a very interesting question from Probability in portion Probability of Mathematics – Class 11

Answer»

The correct choice is (b) 16

To elaborate: Each BULB can have two CASES i.e. either defective or non-defective. Then TOTAL number of OUTCOMES will be 2^4 = 16.



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