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If (4x - 3)/x + (4y - 3)/y + (4z - 3)/z = 0, Then The Value Of 1/x + 1/y + 1/z Is? |
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Answer» (4x - 3)/X + (4Y - 3)/y + (4Z - 3)/z = 0 => 4x/x - 3/x + 4y/y - 3/y + 4z/z - 3/z = 0 => 3/x + 3/y + 3/z = 4 + 4 + 4 = 12 => 1/x + 1/y + 1/z = 12/3 = 4 (4x - 3)/x + (4y - 3)/y + (4z - 3)/z = 0 => 4x/x - 3/x + 4y/y - 3/y + 4z/z - 3/z = 0 => 3/x + 3/y + 3/z = 4 + 4 + 4 = 12 => 1/x + 1/y + 1/z = 12/3 = 4 |
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