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If 5.65 cm long object placed in the front of convex mirror if the height of image will be e formed 7.56 long then find out it's magnification

Answer» TION:u=-5 cm, f=10 cmWe know thatv1 + u1 = F1 ⇒ v1 + (−5)1 = 101 ⇒ v1 = 201 + 51 = 103 ∴v= 310 cm=3.33cmThe position of the image is 3.33 cm behind the convex mirror.Magnification, m=− UV =− −53.33 =0.66The image is virtual and erect.


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