If 60 % of a first order reaction was completed in 60 minutes, 50 % of the same reaction would be completed in approximately [log = 4 = 0.60, log 5 = 0.69].A. 45 minutesB. 60 minutesC. 40 minutesD. 50 minutes.

If 60 % of a first order reaction was completed in 60 minutes, 50 % of

1.	If 60 % of a first order reaction was completed in 60 minutes, 50 % of the same reaction would be completed in approximately [log = 4 = 0.60, log 5 = 0.69].A. 45 minutesB. 60 minutesC. 40 minutesD. 50 minutes.
Answer» Correct Answer - A a) For first order reaction `k=(2.303)/(60 "min") log 100/40` `=(2.303)/(60"min") log 2.5` `=(2.303 xx 2.5)/(60 "min") = 0.0153` `t-(1//2) = 0.693/k = 0.693/(0.0153)=45.3` min.

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If 60 % of a first order reaction was completed in 60 minutes, 50 % of the same reaction would be completed in approximately [log = 4 = 0.60, log 5 = 0.69].A. 45 minutesB. 60 minutesC. 40 minutesD. 50 minutes.

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