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If 7 times the 7th term of an AP is equal to 11 times its 11th term, then its 18th term will be A. 7 B. 11 C. 18 D. 0 |
Answer» D. 0 Let a and d be first term and common difference respectively According to the question, 7 times the 7th term of an AP is equal to 11 times its 11th term ⇒ 7a7 = 11a11 As we know, nth term of an AP is an = a + (n - 1)d where a = first term an is nth term d is the common difference we have, 7(a + 6d) = 11(a + 10d) ⇒ 7a + 42d = 11a + 110d ⇒ 4a + 68d = 0 ⇒ a + 17d = 0 ⇒ a18 = 0 18th term of AP is 0 |
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