1.

If 7th and 13th terms of an A.P. be 34 and 64 respectively, then its 18th term is A. 87 B. 88 C. 89 D. 90

Answer»

Option : (C)

Here,

a7 = 34 and a13 = 64 

i.e.,

a + 6d = 34 ...(i) 

And,

a +12d = 64 ...(ii) 

Subtracting (i) from (ii) we get, 

(12-6) d = 64 - 34 

∴6d = 30 

∴ d = 5 

Substituting d = 5 in (i) we get, 

a+6(5) = 34 

∴a + 30 = 34 

∴ a = 4 

Now,

18th term is given by a18 = a+17d 

= 4+17×5 

= 89



Discussion

No Comment Found