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If 7th and 13th terms of an A.P. be 34 and 64 respectively, then its 18th term is A. 87 B. 88 C. 89 D. 90 |
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Answer» Option : (C) Here, a7 = 34 and a13 = 64 i.e., a + 6d = 34 ...(i) And, a +12d = 64 ...(ii) Subtracting (i) from (ii) we get, (12-6) d = 64 - 34 ∴6d = 30 ∴ d = 5 Substituting d = 5 in (i) we get, a+6(5) = 34 ∴a + 30 = 34 ∴ a = 4 Now, 18th term is given by a18 = a+17d = 4+17×5 = 89 |
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