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If 9th term of an A.P. is zero, prove that its 29th term is double the 19th term. |
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Answer» a9 = 0 a + (9 – 1)d =0 a + 8d = 0 a = - 8d …(i) To Prove: a29 = 2a19 Proof: LHS= a29 = a + 28d = - 8d + 28d = 20d RHS= 2a19 = 2[a + (18)d] = 2(- 8d + 18d) = 2(10d) = 20d Since, LHS=RHS Hence, proved |
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