If `a > 1, b > 1,` then the minimum value of `log_b a + log_a b` is

1.	If `a > 1, b > 1,` then the minimum value of `log_b a + log_a b` is
Answer» Correct Answer - C Using `A.M.geG.M.,` wc have `(log_(b)a+log_(a)b)/(2)gesqrt(log_(b)alog_(a)b)` `impliescos^(3)theta+sec^(3)thetage2.` Hence, the minimum value of `log_(b)a+log_(a)b` is 2 and it is attained when a=b.

Discussion

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