If a 10C charge is placed in a medium having relative permittivity 5.4, what will be the amount of flux coming out of that charge?(a) 1*10^11 Nm^2C^-1(b) 2.1*10^11 Nm^2C^-1(c) 2.1*10^10 Nm^2C^-1(d) 7.1*10^11 Nm^2C^-1I had been asked this question during an interview for a job.I need to ask this question from Application of Gauss’s Law in section Charges and Fields of Physics – Class 12

If a 10C charge is placed in a medium having relative permittivity 5.4

1.	If a 10C charge is placed in a medium having relative permittivity 5.4, what will be the amount of flux coming out of that charge?(a) 110^11 Nm^2C^-1(b) 2.110^11 Nm^2C^-1(c) 2.110^10 Nm^2C^-1(d) 7.110^11 Nm^2C^-1I had been asked this question during an interview for a job.I need to ask this question from Application of Gauss’s Law in section Charges and Fields of Physics – Class 12
Answer» CORRECT answer is (B) 2.110^11 Nm^2C^-1 The explanation: GAUSS’s Law states that electric flux coming out of a charge is=\(\frac {AMOUNT \, of \, charge}{permittivity \, of \, the \, medium}\). In this case, the charge is 1C and permittivity of the medium=5.48.8510^-12. Substituting the values, we get the total flux coming out of the charge is 2.110^11 Nm^2C^-1.

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