

InterviewSolution
Saved Bookmarks
1. |
If A(1,3) B(-1,2) C(2,5) and D(x,4) are the vertices of a ||gm ABCD then the value of x is(a) 3(b) 4(c) 0(d) 3/2 |
Answer» Correct answer is (b) 4 The diagonals of a parallelogram bisect each other. The vertices of the 11gm ABCD are A(1,3), B(-1,2) and C(2,5) and D(x,4) Here, AC and BD are the diagonals. So \(\frac{1\,+\,2}{2}=\frac{-1\,+\,x}{2}\) \(\Rightarrow\) x - 1 = 3 \(\Rightarrow\) x = 1 + 3 = 4 |
|