1.

If A(1,3) B(-1,2) C(2,5) and D(x,4) are the vertices of a ||gm ABCD then the value of x is(a) 3(b) 4(c) 0(d) 3/2

Answer»

Correct answer is (b) 4

The diagonals of a parallelogram bisect each other. The vertices of the 11gm ABCD are

A(1,3), B(-1,2) and C(2,5) and D(x,4)

Here, AC and BD are the diagonals. So

\(\frac{1\,+\,2}{2}=\frac{-1\,+\,x}{2}\)

\(\Rightarrow\) x - 1 = 3

\(\Rightarrow\) x = 1 + 3 = 4



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