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If A = 30°, B = 60° and C = 135°, then what is the value of sin3A + cos3B + tan3C – 3sin A cos B tan C?1). 02). 13). 84). 9 |
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Answer» To find : sin3(30°) + cos3(60°) + tan3(135°) – 3sin (30°) cos (60°) tan (135°) ⇒ (1/2) 3 + (1/2) 3 + (-1) 3 – 3 X (1/2) x (1/2) x (-1) ⇒ 1/8 + 1/8 -1 + 3/4 ⇒ 1/4 – 1 + 3/4 ⇒ 0 |
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