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If A, B and C are the angles of a ∆ABC, prove that tan (C + A)/2 = cot B/2. |
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Answer» Given function is : tan (C + A)/2 = cot B/2 Sum of all the angles of a triangle = 180 degree So, A + B + C = 180° Or A + C = 180° – B And, (A + C)/2 = (180° – B)/2 = 90° – B/2 Now, tan (A + C)/2 = tan(90° – B/2) = cot B/2 Hence Proved. |
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