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    				| 1. | If α,β are roots of the equation (x–a)(x–b)+c = 0 (c ≠ 0), then then roots of the equation (x – c – α)(x – c – β) = c are(a) a and b + c(b) a + c and b(c) a + c and b + c(d) None of these | 
| Answer» Correct option (c) a+c and b+c Explanation: x2 – (a + b)x + ab + c = 0 α + β = a + b and α β = ab + c Now (x – c – α)(x – c – β ) = c ⇒ (x–c)2 – (α + β)(x – c) + α β – c = 0 (x – c)2 – (a + b)(x – c) + ab = 0 (x – c)2– a(x – c) – b(x – c) + ab = 0 ⇒ (x – c – a)(x – c – b) = 0 x = c + a and b + c | |