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The values of p for which 6 lies between the roots of the equation x2 + 2(p – 3)x + 9 = 0 is(a) (-∞, -3/4)(b) (-∞, -3/4)(c) (-∞, 1)(d) none of these |
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Answer» Correct option (a) (-∞, -3/4) Explanation: D > 0 (– 2(p – 3))2 – 4.1.9 > 0 p2 – 6p > 0 p (p – 6) > 0 p < 0, p > 6 .....(1) a.ƒ(6) < 0 1.(36 + 12(p – 3) + 9)) < 0 12p + 9 < 0 P < -3/4 ...(2) From (1) and (2) P ∈ (-∞, -3/4) |
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