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If a,b,c are any three consecutive integers , prove that `log(1+ac)=2logb`A. `"log" b`B. `"log" ((b)/(2))`C. `"log" (2b)`D. `2"log"b`

Answer» Correct Answer - D
Since a, b, c are three consective positive integers,
`therefore b = a + 1, c= a + 2 " and " 2b = a+ c`
Now,
`"log" (1+ca)`
`= "log"{1+(a+2)a} = "log" (a+1)^(2) = 2"log" (a+1) = 2 "log" b`


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