InterviewSolution
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InterviewSolution
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The solution set of `|x+2|^(log_(10)(x^(2)+6x+9))=1` is ______.A. `{-3, -4}`B. `{0, -3}`C. `{-4, -1}`D. `{-3, -1}` |
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Answer» Correct Answer - C Given, `|x+2|^(log_(10)x^(2) + 6x+ 9) = 1` As the RHS = 1 The exponent of x + 2 should be 0 `(a^(0) = 1)` or `|x + 2| = 1` `implies log_(10) x^(2) + 6x + 9 = 0 or x + 2 = pm 1` `x^(2) + 6x + 9 = 1 or x = - 1 or - 3` `x = -2 or -4` `x = -1 or -3` when x = -3, `log_(10)(x^(2) + 6x + 9)` is not defined. When x = -2, |x + 2| = 0 which is not possible. x = -4, or -1. |
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