1.

If `x^(2) + y^(2) -3xy = 0 and x gt y` then find the value of `log_(xy)(x-y)`.A. `1/4`B. 4C. `1/2`D. 2

Answer» Correct Answer - C
Given ` x^(2) + y^(2) - 3xy =0`
` x^(2) + y^(2) - 2xy= xy`
Applying log on both sides,
` log(x-y)^(2) = logxy`
`2log ( x-y) = log xy`
` (log(x-y))/(log xy) = 1/2`
`Rightarrow (x-y)= 1/2`


Discussion

No Comment Found