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If `x^(2)+y^(2)-3xy = 0 and x gt y` then find the value of `log_(xy)(x-y)^2`A. `1/4`B. 4C. `1/2`D. 2 |
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Answer» Correct Answer - C Given `x^(2) + y^(2) - 3xy =0` ` x^(2) + y^(2) - 2xy = xy` Applying log on both sides ` log (x - y^(2)) = log xy` ` 2 log (x-y) = log xy` ` Rightarrow ( log(x-y))/(log xy) = 1/2` `Rightarrow log_(xy) (x-y) = 1/2` |
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