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If a, b, c are in A.P., prove that : a2 + c2 + 4ac = 2 (ab + bc + ca) |
Answer» a2 + c2 + 4ac = 2 (ab + bc + ca) a2 + c2 + 2ac - 2ab - 2bc = 0 (a + c - b)2 – b2 = 0 a + c - b = b a + c - 2b = 0 Since, a, b, c are in AP b - a = c - b a + c - 2b = 0 Hence proved. |
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