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If A + B + C = π, Prove that tan A + tan B + tan C = tan A . tanB · tan C |
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Answer» Given A + B + C = π ⇒ A + B = π – C tan(A + B) = tan(180 – C) \(\frac{tanA + tanB}{1 - tanA.tanB} = - \frac{tanc}{1}\) tanA + tanB = – tanc – tanB tanB · tanc tanA + tanB + tanC = tanA tanB tanC |
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