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If a+b is along the angle bisector of a and b, where `|a|=lamda|b|`, then the number of digits in value of `lamda` is |
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Answer» Correct Answer - 1 Since, angle bisector of a and b `impliesh(hata+hatb)=h((a)/(|a|)+(b)/(|b|))` . . . (i) Given, a+b is alongg angle bisector `implies mu((a)/(|a|)+(b)/(|b|))=a+b` only, when `|a|=|b|=mu` `therefore|a|=|b| implies lamda=1`. |
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