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If (a, b) is the mid-point of the line segment joining the points A (10, -6), B(k, 4) and a – 2b = 18, find the value of k and the distance AB. |
Answer» As (a, b) is the mid-point of the line segment A(10, -6) and B(k, 4) So, (a, b) = (10 + k / 2, -6 + 4/ 2) a = (10 + k)/ 2 and b = -1 2a = 10 + k k = 2a – 10 Given, a – 2b = 18 Using b = -1 in the above relation we get, a – 2(-1) = 18 a = 18 – 2 = 16 So, k = 2(16) – 10 = 32 – 10 = 22 Thus, AB = √[(22 – 10)2 + (4 + 6)2] = √[(12)2 + (10)2] = √[144 + 100] = 2√61 units |
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