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If a ball is thrown vertically upwards with speed `u`, the distance covered during the last `t` second of its ascent isA. utB. `(1)/(2)"gt"^(2)`C. `ut-(1)/(2)"gt"^(2)`D. `(u+gt)t` |
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Answer» Correct Answer - B Distance convered in last t second of ascent = distance covered in first 1 second of descent `=0+(1)/(2)"gt"^(2)` |
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