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. if a body loses half of its velocity on penetrating 3 cm in a wooden block, then how much will t penetratemore before coming to rest?(1) 1 cm(2) 2 cm(3) 3 cm(4) 4 cm |
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Answer» With penetrating 3 cm block, v^2/4 = v^2 – 2a*3 3v^2/4 = 6a v^2 = 8a.........(1) Now, 0^2 = v^2 – 2ax.......(2) put (1) in (2) x = 1 cm net distance would be => 1 + 3 =4cm |
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