1.

. if a body loses half of its velocity on penetrating 3 cm in a wooden block, then how much will t penetratemore before coming to rest?(1) 1 cm(2) 2 cm(3) 3 cm(4) 4 cm

Answer»

With penetrating 3 cm block,

v^2/4 = v^2 – 2a*3

3v^2/4 = 6a

v^2 = 8a.........(1)

Now,

0^2 = v^2 – 2ax.......(2)

put (1) in (2)

x = 1 cm

net distance would be => 1 + 3 =4cm



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