1.

if a body weighing 40 kg is taken inside the earth to a depth of 143 radius of the earth the weight of the body at that point is

Answer»

EXPLAINATION:

f = g \times \frac{m1 \times m2}{ {d}^{2} }

= 6.67 \times {10}^{ - 11} \times \frac{40 \times 5.97 \times {10}^{24} }{ {143}^{2} }

= {10}^{13} \times \frac{6.67 \times 40 \times 5.97}{ {143}^{2} }

= 0.077 \times {10}^{13}

= 7.7 \times {10}^{11}


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